The diameters of the lower and upper ends of a bucket in the form of a frustum of a cone are 10 cm and 30 cm respectively. If its height is 24 cm, then the area of the metal sheet used to make the bucket is _____. (Use π = 3.14)
A
1711.3cm2
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B
17.113m2
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C
1.7113m2
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D
1711.3mm2
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Solution
The correct option is A1711.3cm2 Given, Height of frustum, h=24 cm Diameter of lower end, d =10 cm So, Radius of lower end, r = 5 cm Diameter of upper end D = 30 cm So, Radius of upper end, R=15 cm
Slant height of the frustum, l=√h2+(R−r)2 =√(24)2+(15−5)2 =√576+100 =√676 =26cm
Area of metal sheet used to make the bucket = Curved surface area of frustum + Area of base =πl(R+r)+πr2 =π[26(15+5)+(5)2] =3.14(520+25) =3.14×545 =1711.3cm2