Option (B) is correct.
Given , diameter of one end of the bucket,
2R=44⇒R=22 cm [∵diameter,d=2×radius]
And diameter of the other end.
2r=24⇒r=12 cm [∵diameter,d=2×radius]
Height of the bucket , h = 35 cm
Since, the shape of bucket is look like as frustum of cone.
∴ Capacity of the bucket = Volume of the frustum of the cone
=13πh[R2+r2+Rr]=13×π×35[(22)2+(12)2+22×12]=35π3[484+144+264]=35π×8923=35×22×8923×7=32706.6 cm3(approx)=32.7L[∵1000 cm3=1 L]