Question

The diameters of two steel wires are in the ratio 2: 3. Their lengths are equal. When same force is applied on them, the ratio of the elongation produced is

• A. $4:9$
• B. $9:4$
• C. $3:2$
• D. $2:3$

Answer 1

The correct option is B $9:4$

$\frac{r_1}{r_2}=\frac{2}{3}$
$\frac{A_1}{A_2}=\frac{4}{9}$
$\frac{\Delta L_1}{\Delta L_2}=\frac{A_2}{A_1}$$=9/4$