The difference between a 2-digit number and the number obtained by interchanging its digits is 63. What is the difference between the digits of the number?

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Solution

Let the numbers be x and y
the number at ones place is y
and number on tens place is $10 x$
so the digit will be $10 x + y$
The interchange of digit is $= 10 y + x$
It is given the difference between the digit and interchange is $63$ so
$10 x + y - (10 y + x) = 63$
$9 x - 9 y = 63$
$x - y = 7$
The difference between the digits is $7$ .

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The difference between a 2-digit number and the number obtained by interchanging its digits is 63. What is the difference between the digits of the number?

Let the numbers be x and ythe number at ones place is yand number on tens place is 10xso the digit will be 10x+yThe interchange of digit is =10y+xIt is given the difference between the digit and interchange is 63 so10x+y−(10y+x)=639x−9y=63x−y=7The difference between the digits is 7.