The difference between a two – digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the tenths digit to that of the units digit of the number is 2:1?

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Solution

The correct option is B
8

Since the number is greater then the number obtained on reversing the digits, so the ten's digit is greater than the unit's digits Let the ten's and unit's digits be 2x and x respectively Then, $(10 \times 2 x + x) - (10 x + 2 x) = 36 \Leftrightarrow 9 x = 36 \Leftrightarrow x = 4.$ $∴$ Required differences = $(2 x + x) - (2 x - x) = 2 x = 8.$

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