The difference between a two - digit number and the number obtained by interchanging the position of both the digits is 63. Which is the smallest two digit number that satisfies the above condition ?
81
Let the ten's digit be x and unit's digit be y Then, (10x+y)−(10y+x)=63⇔9(x−y)=63⇔x−y=7. Thus, 81 is the smallest two digit number that satisfies the given condition.