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Question

The difference between a two - digit number and the number obtained by interchanging the position of both the digits is 63. Which is the smallest two digit number that satisfies the above condition ?


A

29

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B

70

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C

49

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D

56

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E

81

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Solution

The correct option is E

81


Let the ten's digit be x and unit's digit be y Then, (10x+y)(10y+x)=639(xy)=63xy=7. Thus, 81 is the smallest two digit number that satisfies the given condition.


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