The difference between a two – digit number and the number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number?

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Solution

The correct option is B
4

Let the ten's digit be x and unit's digit be y

Then, $(10 x + y) - (10 y + x) = 36 \Leftrightarrow 9 (x - y) = 36 \Leftrightarrow x - y = 4.$

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The difference between a two – digit number and the number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number?

The correct option is B 4 Let the ten's digit be x and unit's digit be y Then, (10x+y)−(10y+x)=36⇔9(x−y)=36⇔x−y=4.

The correct option is B
4

Let the ten's digit be x and unit's digit be y

Then, $(10 x + y) - (10 y + x) = 36 \Leftrightarrow 9 (x - y) = 36 \Leftrightarrow x - y = 4.$