Question

The difference between bond orders of $CO$ and $N{O}^{+}\text{is}\frac{x}{2}$where x is (Round off to the Nearest Integer)

Answer 1

Bond order of $CO=3$
$\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p_z^2\pi 2p_x^2\pi 2p_y^2$
$B.O.=\frac{10-4}{2}=3$
$N{O}^{+}:$
$B.O.=\frac{8-2}{2}=3$
Difference = 3 - 3 = 0