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Limitations of First Law

The differenc...

Question

The difference between heat of reactions at constant pressure and constant volume for the reaction $C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l)$ at $25^{\circ} C$ in kJ is

-7.43

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3.72

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-3.72

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7.43

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Solution

The correct option is C -3.72
We have the relation for a reaction
$△ H - △ U = △ n_{g} R T$
$2 C_{6} H_{6} (l) + 15 O_{2} (g) \to 12 C O_{2} (g) + 6 H_{2} O (l)$ at $25^{\circ} C$
here $Δ n_{g} = 6 - \frac{15}{2} = - 1.5$
Putting the values in the formula we get,
$△ H - △ U = (- 1.5) \times \frac{8.314}{1000} \times 298 △ H - △ U = - 3.716 k J m o l^{- 1}$

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Similar questions

25^{o} C

C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l)

Δ H = - 780980 c a l

25^{o} C,

C_{6} H_{6} (l) + 7 \frac{1}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l); △ U = - 780980 c a l

25^{o} C

C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l)

Δ H = - 780980 k c a l

2 C_{6} H_{6} (l) + 15 O_{2} (g) \to 12 C O_{2} (g) + 6 H_{2} O (l)

25^{\circ} C

k J

△ H

△ U

k J

C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l)

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