CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Limitations of First Law

The differenc...

Question

The difference between heat of reactions at constant pressure and constant volume for the reaction $C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l)$ at $25^{\circ} C$ in kJ is

A

-7.43

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

3.72

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

-3.72

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

7.43

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C -3.72
We have the relation for a reaction
$△ H - △ U = △ n_{g} R T$
$2 C_{6} H_{6} (l) + 15 O_{2} (g) \to 12 C O_{2} (g) + 6 H_{2} O (l)$ at $25^{\circ} C$
here $Δ n_{g} = 6 - \frac{15}{2} = - 1.5$
Putting the values in the formula we get,
$△ H - △ U = (- 1.5) \times \frac{8.314}{1000} \times 298 △ H - △ U = - 3.716 k J m o l^{- 1}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. For the combustion of 1 mol of liquid benzene at

25^{o} C

, the heat of reaction at constant pressure is given by,

C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l)

Δ H = - 780980 c a l

.
What would be the heat of reaction at constant volume?

Q. For the combustion of 1 mole of liquid benzene at

25^{o} C,

the heat of reaction at constant pressure is given by

C_{6} H_{6} (l) + 7 \frac{1}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l); △ U = - 780980 c a l

What would be the heat of reaction at constant volume?

Q. For the combustion of 1 mol of liquid benzene at

25^{o} C

, the heat of reaction at constant pressure is given by,

C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l)

Δ H = - 780980 k c a l

.
What would be the heat of reaction at constant volume?

Q. The difference between the heat of reaction at constant pressure and constant volume for the reaction

2 C_{6} H_{6} (l) + 15 O_{2} (g) \to 12 C O_{2} (g) + 6 H_{2} O (l)

25^{\circ} C

k J

Q. Magnitude of difference between

△ H

△ U

k J

for the combustion of benzene at 300 K is :

C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l)

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Limitations of First Law

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon