According to the question the difference can be x−(−6) or −6−x.
If the difference is x−(−6) then
x−(−6)=−5
x=−5+(−6)=−5−6=−(5+6)
[Taking ′−′ as common ]
⇒ x=−11
∴ The value of x is −11 .
If the difference is −6−x then
−6−x=−5
−x=−5+6
−x=1
x=−1
∴ The other possible value of x is −1.