The difference between radii of 3rd and 4th orbits of Li2+is ΔR1. The difference between the radii of 3rd and 4th orbits of He+is ΔR2. Ratio ΔR1:ΔR2 is
A
3 : 2
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B
8 : 3
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C
2 : 3
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D
3 : 8
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Solution
The correct option is C 2 : 3 rn=a0n2Z
rn∝n2Z r3(Li2+)∝32ZLi2+ r4(Li2+)∝42ZLi2+ ΔR1=r4−r3∝42−32ZLi2+
Similarly for He+ ΔR2=r4−r3∝42−32ZHe+ ∴ΔR1ΔR2=ZHE+ZLi2+=23
Hence, (c) is the correct option