The difference between the acute angles of a right-angled triangle is 2- 5 radians- Express the angles in degrees-

2π5 = 2π5×180/π = 36 × 25 = 725 = 14.4^ ∘ ...

You visited us 5 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VI

Mathematics

Angle

The differenc...

Question

The difference between the acute angles of a right-angled triangle is $\frac{2 π}{5}$ radians. Express the angles in degrees.

Open in App

Solution

$\frac{2 π}{5}$

$= \frac{2 π}{5} \times \frac{180}{π}$

$= \frac{36 \times 2}{5} = \frac{72}{5}$

$= {14.4}^{\circ}$

Suggest Corrections

Similar questions

The difference between the two acute angles of a right - angled triangle is $\frac{2 π}{5}$ radians. Express the angles in degrees.

Q. One angle of a triangle

\frac{2}{3}

x grades and another is

\frac{3}{2}

x degrees while the third is

\frac{πx}{75}

radians. Express all the angles in degrees.

In a right angled triangle, acute angles A and B satisfy

tan A + tan B + {tan}^{2} A + {tan}^{2} B + {tan}^{3} A + {tan}^{3} B = 70

find the angle A and B in radians.

Q. What is the measure of the acute angle in the right-angled isosceles triangle in degrees?

One angle of a triangle is $\frac{2}{3} x$ grades and another is $\frac{3}{2} x$ degrees while the third is $\frac{π x}{75}$ radians. Express all the angles in degrees.

Join BYJU'S Learning Program

The difference between the acute angles of a right-angled triangle is 2π5 radians. Express the angles in degrees.

2π5=2π5×180π=36×25=725=14.4∘

The difference between the acute angles of a right-angled triangle is $\frac{2 π}{5}$ radians. Express the angles in degrees.

$\frac{2 π}{5}$

$= \frac{2 π}{5} \times \frac{180}{π}$

$= \frac{36 \times 2}{5} = \frac{72}{5}$

$= {14.4}^{\circ}$