The difference between the largest and the smallest angle of the given triangle is

∠ B - ∠ C

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∠ C - ∠ B

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∠ A - ∠ B

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∠ B - ∠ A

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Solution

The correct option is C $∠ A - ∠ B$
Given, in $Δ A B C$ , AC = 5 cm, AB = 9 cm and BC = 12 cm.
Hence, the ascending order of sides is AC, AB, BC.
In any triangle, the angle opposite to the longer side is larger.
$∴$ Ascending order of angles is $∠ B, ∠ C, ∠ A$ .
$\Rightarrow ∠ B < ∠ C < ∠ A$
$∴$ The difference of the largest and the smallest angle of the given triangle is given by $∠ A - ∠ B$ .

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