Question

The difference between the measure of two angles of a linear pair is ${80}^o$, then the smaller angle is___________________

Answer 1

$\begin{array}{c}SumoflinearPairatangleis{180}^{\circ }\\ let,oneangle=x\\ otherangley={180}^{\circ }-x\\ fromquestion\\ x-\left({180}^{\circ }-x\right)={80}^{\circ }\\ x-{180}^{\circ }+x={80}^{\circ }\\ 2x={260}^{\circ }\\ x={130}^{\circ }\\ \therefore y={180}^{\circ }-{130}^{\circ }={50}^{\circ }smallerangle\end{array}$

Hence, this is the answer.