The difference between the place values of 6 and 3 in 256839 is
(a) 3
(b) 9
(c) 6800
(d) 5930

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Solution

The options given are incorrect.
The place value of 6 in 2,56,839 = 6 thousands = 6,000
The place value of 3 in 2,56,839 = 3 tens = 30
∴ Difference = 6,000 − 30 = 5,970

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