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Question

The difference between the sum of first 100 natural numbers and the sum of even numbers from 1 to 100.


A

2200

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B

2400

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C

2500

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D

2700

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Solution

The correct option is C

2500


Sum of first 100 natural numbers = 1002(2+99)=5050

Sum of even numbers from 1 to 100, there are 50 even numbers between 1 and 100.

So, the sum of the 50 even numbers between 1 and 100 =502(2×2+49×2)=2550.
=502(2×2+49×2)=2550.

So, the difference is 5050 - 2550 = 2500


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