The difference between two numbers is 26 and one number is three times the other. Find the numbers.

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Solution

Let the larger number be x and the smaller number be y.
Then, we have:
x − y = 26 ...(i)
x = 3y ...(ii)
On substituting x = 3y in (i), we get:
3y − y = 26 ⇒ 2y = 26 ⇒ y = 13
On substituting y = 13 in (i), we get:
x − 13 = 26 ⇒ x = 26 + 13 = 39
Hence, the required numbers are 39 and 13.

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The difference between two numbers is 26 and one number is three times the other. Find the numbers.

Let the larger number be x and the smaller number be y. Then, we have: x − y = 26 ...(i) x = 3y ...(ii) On substituting x = 3y in (i), we get: 3y − y = 26 ⇒ 2y = 26 ⇒ y = 13 On substituting y = 13 in (i), we get: x − 13 = 26 ⇒ x = 26 + 13 = 39 Hence, the required numbers are 39 and 13.

Let the larger number be x and the smaller number be y.
Then, we have:
x − y = 26 ...(i)
x = 3y ...(ii)
On substituting x = 3y in (i), we get:
3y − y = 26 ⇒ 2y = 26 ⇒ y = 13
On substituting y = 13 in (i), we get:
x − 13 = 26 ⇒ x = 26 + 13 = 39
Hence, the required numbers are 39 and 13.