The difference between two positive integers is 3. If the sum of their squares is 369, then the sum of the numbers is
27
Let the numbers be x and (x + 3), Then,
x2 + (x+3)2 = 369
⟹x2 + 3x -180 = 0
⟹(x+15)(x-12) = 0
∴ x = 12 (since -15 is not possible)
So, the numbers are 12 and 15.
∴ Required sum = (12 + 15) = 27.