Question

The difference in angular momentum associated with the electron in two successive orbits of hydrogen atom is:

• A. $\frac{h}{\pi }$
• B. $\frac{2h}{\pi }$
• C. $\frac{nh}{2\pi }$
• D. $\frac{h}{2\pi }$

Answer 1

The correct option is D $\frac{h}{2\pi }$

According to Bohr's postulate, the angular momentum is,

$L=\frac{nh}{2\pi }$

Let's take two successive orbit as $n_1=n\text{and}{n}_2=n+1$

$\Rightarrow L_1=\frac{nh}{2\pi }$ and $L_2=\frac{(n+1)h}{2\pi }$

$\therefore \Delta L=L_2-L_1=\frac{(n+1)h}{2\pi }-\frac{nh}{2\pi }$

$\Rightarrow \Delta L=\frac{h}{2\pi }$

Hence, option $\left(D\right)$ is correct.

Why this Question? Checks the understanding of angular momentum and Bohr's second postulate.