The difference in angular momentum of electrons between any two successive orbits in an atom is :

\frac{h}{2 π}

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\frac{2 h}{3 π}

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\frac{3 h}{5 π}

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Cannot be determined

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Solution

The correct option is A $\frac{h}{2 π}$
The difference in angular momentum of electrons = $\frac{Δ n h}{2 π}$
Therefore difference in angular momentum of electrons between any two successive orbits in an atom is ; $\frac{h}{2 π}$

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The orbital angular momentum of an electron in 2 $s^{-}$ orbital is

^{'} s^{'}

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