Question

The difference in angular momentums associated with an electronic transition in hydrogen atom is equal to $3h/2\pi$ . The atom contains only K, L, M and N shells. Calculate the energies and radii associated with the orbits.

Answer 1

$\Delta L=\frac{3h}{2\pi }(n=1ton=4)$

Transition is from $n=1$ to $n=4$ (K to N)

$E_K=-13.6\times \frac{1}{1}=-13.6eV{E}_N=-13.6\times \frac{1}{16}=-0.822eV{r}_k=0.529\times \frac{n^2}{z}{A}^{\circ }=0.529A^{\circ }{r}_k=0.529\times \frac{16}{1}{A}^{\circ }=8.464A^{\circ }$