Question

The difference in $\Delta H$ and $\Delta E$ for the reaction, $BaC{l}_2\left(aq\right)+K_{2}S{O}_4\left(aq\right)\to BaS{O}_4\left(s\right)+2KCl\left(aq\right)$ is :

• A. $RT$
• B. $2RT$
• C. Zero
• D. Cannot be predicted

Answer 1

The correct option is C Zero

$\Delta H=\Delta E+\Delta n_{g}RT$

$\Delta n_g=$ difference of moles of gaseous molecules $=0$

$\therefore \Delta H=\Delta E$

$\therefore \Delta H-\Delta E=0$