Question

The difference in the effective capacity of two similar capacitors when joined in series and then in parallel is $6\mu F$. The capacity of each capacitor is

• A. $2\mu F$
• B. $4\mu F$
• C. $8\mu F$
• D. $16\mu F$

Answer 1

The correct option is B $4\mu F$

Let the capacitance of each capacitor be $C$.

Equivalent capacitance of the two capacitors connected in parallel $C_p=C+C=2C$

Equivalent capacitance of the two capacitors connected in series $C_s=\frac{CC}{C+C}=\frac{C}{2}$

But, $C_p-C_s=6\mu F$

Or $2C-\frac{C}{2}=6\mu F$

OR $\frac{3C}{2}=6\mu F$

$⟹$ $C=4\mu F$