Question

The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two.

The metal ion is :

• A. $F{e}^{2+}$
• B. $C{o}^{2+}$
• C. $M{n}^{2+}$
• D. $N{i}^{2+}$

Answer 1

The correct option is B $C{o}^{2+}$

The difference in the number of unpaired electrons of Metal ion in its high-spin and low-spin octahedral complexes is 2.

For the metal ${Co}^{2+}\left(\right[Ar\left]3d^7\right)$ ion, the difference of unpaired electrons is $3-1=2$ since the number of unpaired electrons of a metal ion in its high-spin complex is 3 and low-spin complex is 1.

Option B is correct