The difference in the oxidation numbers of the two types of sulphur atoms in $N a_{2} S_{4} O_{6}$ is:

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Solution

O.S. of first sulphur: Sulphur is attached to the same sulphur atoms hence there is no change in the electronic arrangement of this sulphur atom, therefore its O.S. is zero

O.S. of second sulphur: This atom of sulphur is attached to the three oxygen atoms two are doubly bonded and one is singly bonded.

Therefore, for doubly bonded oxygen will exert the charge +2 and for singly bonded oxygen it will be +1. In total, the O.S of second sulphur is +5

$∴$ Difference in the O.S of the two types of sulphur atoms is 5 - 0 = 5.

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