The difference of 2 complementary angles is 30 degree. Then the angles are

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Solution

Dear student
Let one angle =x
So, other angle =90°-x
A.T.Q
x-(90°-x)=30°
x-90°+x=30°
2x=30°+90°
2x=120°
x=60°
So, angles are 60° and 90°-60°=30°
Regards

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Question 18

The difference fo two complementary angles is $30^{\circ} .$ Then the angles are
(a) $60^{\circ}, 30^{\circ}$
(b) $70^{\circ}, 40^{\circ}$
(c) $20^{\circ}, 50^{\circ}$
(d) $105^{\circ}, 75^{\circ}$

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The difference of 2 complementary angles is 30 degree. Then the angles are

Dear student Let one angle =x So, other angle =90°-x A.T.Q x-(90°-x)=30° x-90°+x=30° 2x=30°+90° 2x=120° x=60° So, angles are 60° and 90°-60°=30° Regards

Dear student
Let one angle =x
So, other angle =90°-x
A.T.Q
x-(90°-x)=30°
x-90°+x=30°
2x=30°+90°
2x=120°
x=60°
So, angles are 60° and 90°-60°=30°
Regards