The difference of a number and its positive squareroot is 42. Express this in quadratic equation form. [Assume positive square root of the number be $x$ ]

x^{2} + x + 42 = 0

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x^{2} - 42 = 0

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x^{2} - x - 42 = 0

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x^{2} - x + 42 = 0

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Solution

The correct option is C $x^{2} - x - 42 = 0$
Let ' $x$ ' be the positive squareroot of the number . Then the number will be $x^{2}$ .
Given that, $x^{2} - x = 42$
$\Rightarrow x^{2} - x - 42 = 0$

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The difference of a number and its positive squareroot is 42. Express this in quadratic equation form. [Assume positive square root of the number be x]

The correct option is C x2−x−42=0Let 'x' be the positive squareroot of the number . Then the number will be x2. Given that, x2−x=42 ⇒x2−x−42=0

The difference of a number and its positive squareroot is 42. Express this in quadratic equation form. [Assume positive square root of the number be $x$ ]

The correct option is C $x^{2} - x - 42 = 0$
Let ' $x$ ' be the positive squareroot of the number . Then the number will be $x^{2}$ .
Given that, $x^{2} - x = 42$
$\Rightarrow x^{2} - x - 42 = 0$