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Question

The difference of area of two squares is A. The difference of their perimeters is p. Then the sum of their perimeters is ______ .



A

2A/p

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B

4A/p

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C

8A/p

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D

16A/p

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Solution

The correct option is B

16A/p


x2 – y2 = A

(x-y)(x+y) = A

 4(x-y)(x+y) = 4A

 x+y = 4 Ap

Sum of perimeters = 4(x + y) = 4(Ap) = 16Ap


Mathematics

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