The difference of the areas of a sector of angle $120^{0}$ and its corresponding major sector of a circle of radius 21 cm is

1386

c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

924

c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

462

c m^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

231

c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 462 $c m^{2}$
$G i v e n - O A P B i s a s e c t o r w i t h c e n t r a l a n g l e = ∠ A O B = θ = 120^{o} a n d t h e r a d i u s o f t h e c i r c l e = r = 21 c m . i . e t h e r a d i u s o f t h e s e c t o r = r = 21 c m . T o f i n d o u t - t h e d i f f e r e n c e b e t w e e n a r . m a j o r s e c t o r a n d a r . m i n o r s e c t o r . S o l u t i o n - T h e a r . m i n o r s e c t o r = \frac{θ}{360^{o}} \times π \times r^{2} = \frac{120^{o}}{360^{o}} \times \frac{22}{7} \times 21^{2} r^{2} = 462 {c m}^{2} . A g a i n a r . c i r c l e = π \times r^{2} = \frac{22}{7} \times 21^{2} {c m}^{2} = 1386 {c m}^{2} . ∴ a r . m a j o r s e c t o r = a r . c i r c l e - a r . m i n o r s e c t o r = (1386 - 462) {c m}^{2} = 924 {c m}^{2} . ∴ a r . m a j o r s e c t o r - a r . m i n o r s e c t o r = (924 - 462) {c m}^{2} = 462 {c m}^{2} . A n s - O p t i o n C .$

Suggest Corrections

Similar questions

Find the difference of the areas of a sector of angle $120^{\circ}$ and its corresponding major sector of a circle of radius 21 cm.

The area in $c m^{2}$ of a sector of a circle with radius 6 cm if angle of the sector is $60^{\circ}$ is ___ $c m^{2}$ .

The area of a sector (in $c m^{2}$ )of a circle with radius 6 cm if angle of the sector is $70^{\circ}$ will be __ $c m^{2}$ . ( Take $π$ = $\frac{22}{7}$ )

Q. Question 20
Find the difference of the areas of a sector of angle

120^{\circ}

and its corresponding major sector of a circle of radius 21 cm.

Q. If the area of the sector of a circle with angle

45^{\circ}

11 c m^{2}

, then the area of corresponding major sector is equal to.

Join BYJU'S Learning Program

The difference of the areas of a sector of angle 1200 and its corresponding major sector of a circle of radius 21 cm is

The difference of the areas of a sector of angle $120^{0}$ and its corresponding major sector of a circle of radius 21 cm is