Question

The difference of the number of $\sigma$-bonds and $\pi$-bonds in the product (blue-coloured) formed by the reaction of $H_2{O}_2$ with dichromate in an acidic medium is:.

Answer 1

$C{r}_2{O}_7^{2-}+4H_2{O}_2+2H^{+}\to 2Cr{O}_5+5H_{2}O$
$Cr{O}_5$ has 7 $\sigma$-bonds and 1 $\pi$-bond.
So, 7-1= 6