Question

The different between to selling prices of a jacket at profits $4$ and $5$ is Rs.$6$. Find the

cost price of the jacket

two selling price of the jacket.

Answer 1

Let the cost of each jacket be $Rs.x$.

Profit on first jacket $=4\%\left(\text{Given}\right)$

Therefore,

Selling price of first jacket $=x+\frac{4}{100}\times x=\frac{26}{25}x$

Profit on second jacket $=5\%\left(\text{Given}\right)$

Therefore,

Selling price of second jacket $=x+\frac{5}{100}\times x=\frac{21}{20}x$

Given that the difference between the selling price of the jackets is $Rs.6$

Therefore,

$\frac{21}{20}x-\frac{26}{25}x=6$

$\frac{105x-104x}{100}=6$

$\Rightarrow x=600$

Hence the cost price of each jacket is $Rs.600$.

Therefore,

Selling price of first jacket $=\frac{26}{25}\times 600=Rs.624$

Selling price of second jacket $=\frac{21}{20}\times 600=Rs.630$

Hence the cost price of each jacket is $Rs.600$ and the selling price of the two jackets ar $Rs.624$ and $Rs.630$ respectively.