You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Chain Rule of Differentiation

The different...

Question

The differential equation obtained by eliminating the arbitrary constants a and b in $y = a c o s (n x + b)$ is

yⁿ=n²y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

yⁿ+y=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

yⁿ+n²y=0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

yⁿ-y=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
yⁿ+n²y=0

$y^{1} = - n^{2} a c o s (n x + b) = - n^{2} y$

Suggest Corrections

Similar questions

Q. If

y = e^{- x} cos x

and

y_{n} + k_{n} y = 0

, where

y_{n} = \frac{d^{n} y}{d x^{n}}

and

k_{n}

are constants

\forall n ϵ N

, then

Q. Obtain the differential equation by eliminating arbitrary constants

A, B

from the equation-

y = A cos (log x) + B sin (log x)

Q. If

y_{n}

is the

n

th derivative of

y

then the least value of

n

so that

y_{n} = y_{n + 1}

where

y = x^{2} + e^{x}

Q. If

y = cos 2 x cos 3 x

, then

y_{n}

is equal to

Where,

y_{n}

denotes the

n^{t h}

derivative of

y

Q. lf

y = \frac{1}{x^{2} - a^{2}}

then

y_{n} =

(where

y_{n}

denotes the

n^{t h}

derivative of

y

w.r.t.

x

)

Join BYJU'S Learning Program

The differential equation obtained by eliminating the arbitrary constants a and b in y=a cos(nx+b) is

The correct option is C yn+n2y=0 y1=−n2 a cos(nx+b)=−n2y

The differential equation obtained by eliminating the arbitrary constants a and b in $y = a c o s (n x + b)$ is

The correct option is C
yⁿ+n²y=0

$y^{1} = - n^{2} a c o s (n x + b) = - n^{2} y$