The differential equation of a particle executing SHM along y-axis is

\frac{d^{2} y}{d t^{2}} + ω^{2} y = 0

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\frac{d^{2} y}{d t^{2}} - ω^{2} y = 0

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\frac{d^{2} x}{d t^{2}} + ω^{2} x = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{d^{2} x}{d t^{2}} - ω^{2} x = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is C $\frac{d^{2} y}{d t^{2}} + ω^{2} y = 0$
This is factual. A particle executing SHM along y-axis will have the following equation of motion:
$\frac{d^{2} y}{d t^{2}} + ω^{2} y = 0$

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Similar questions

Q. If

x = a cos ω t + b sin ω t

then prove that

\frac{d^{2} x}{d t^{2}} + ω^{2} x = 0

Q. If

x = a (cos t + t sin t)

and

y = a (sin t - t cos t), 0 < t < \frac{π}{2}

, find

\frac{d^{2} x}{d t^{2}}, \frac{d^{2} y}{d t^{2}}

and

\frac{d^{2} y}{d x^{2}} .

The second derivative of a single valued function parametrically represented by $x = ϕ (t) a n d y = ψ (t)$ , ( where $ϕ (t) a n d ψ (t)$ are different functions and $ϕ^{'} (t) \neq 0$ ) is given by

Q. The degree of the differential equation

\frac{d^{2} x}{d t^{2}} + 2 x^{3} = 0

Q. The equation of motion of a particle executing SHM is

(\frac{d^{2} x}{d t^{2}}) + k x = 0

. The time period of the particle will be ?

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The differential equation of a particle executing SHM along y-axis is

The correct option is C d2ydt2+ω2y=0This is factual. A particle executing SHM along y-axis will have the following equation of motion:d2ydt2+ω2y=0

The correct option is C $\frac{d^{2} y}{d t^{2}} + ω^{2} y = 0$
This is factual. A particle executing SHM along y-axis will have the following equation of motion:
$\frac{d^{2} y}{d t^{2}} + ω^{2} y = 0$