wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The differential equation of all circles passing through the origin and with centres on x- axis is:

A
x2y2+2xydydx=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x2+y22xydydx=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2y22xydydx=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x2+y2+2xydydx=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x2y2+2xydydx=0
(x4)2+y2=y2
2(x4)+2yy1=0
(x4)yy1
4=x+yy1
y2y21+y2=x2+y2y21+2xyy1
x2y2+2xydydx=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Formation of Differential Equation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon