wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The differential equation of family of coaxial circle x2+y2+2λx+c=0 is

A
y.d2ydx2+(dydx)2+1=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
y.d2ydx2+(dydx)2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(d2ydx2)+(dydx)2+1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
d2ydx2+(dydx)2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A y.d2ydx2+(dydx)2+1=0
x2+y2+2x+c=0
2x+2ydydx+2ϕ=0
x+ydydx+ϕ=0
1+(dydx)2+yd2ydx2=0
y(d2ydx)+(dydx)2+1=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon