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Question

The differential equation representing the family of curves y2=a(ax+b) where a and b are arbitrary constants, is of

A
order 1,degree 1
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B
order 1,degree 3
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C
order 2,degree 3
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D
order 1,degree 4
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E
order 2,degree 1
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Solution

The correct option is D order 2,degree 1
we have y2=a(ax+b)
y2=a2x+ab
On differentiating w.r.t x we get
2ydydx=a2
ydydx=a22
yd2ydx2+dydx.dydx=0
y.y2+(y1)2=0
Hence order and degree of the given equation is 2 and 1, respectively

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