The differential equation representing the family of curves y 2- c x -2 c - where C is positive parameter- is ofA- order -1- degree -2B- order -2- degree -2C- order -1- degree -3D- order -2- degree -4

The correct option is C order = 1, degree = 3y^2 = √(c) (x +2c) Differentiating w.r.t. x, 2y dy/dx = √(c) ∴ y^2 = 2ydy/dx(x + 2 (2y dy/dx)^2 ) Hence nbsp;or ...

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Standard XII

Mathematics

Formation of a Differential Equation from a General Solution

The different...

Question

The differential equation representing the family of curves $y^{2} = \sqrt{c} (x + 2 c)$ , where $c$ is positive parameter, is of

order

= 1

, degree

= 2

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order

= 2

, degree

= 2

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order

= 1

, degree

= 3

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order

= 2

, degree

= 4

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Solution

The correct option is C order $= 1$ , degree $= 3$
$y^{2} = \sqrt{c} (x + 2 c)$
Differentiating w.r.t. $x$ ,
$2 y \frac{d y}{d x} = \sqrt{c}$
$∴ y^{2} = 2 y \frac{d y}{d x} (x + 2 {(2 y \frac{d y}{d x})}^{2})$

Hence order $= 1$ , degree $= 3$

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The differential equation representing the family of curves y2=√c(x+2c), where c is positive parameter, is of

The correct option is C order =1, degree =3y2=√c(x+2c) Differentiating w.r.t. x, 2ydydx=√c ∴y2=2ydydx(x+2(2ydydx)2) Hence order =1, degree =3

The differential equation representing the family of curves $y^{2} = \sqrt{c} (x + 2 c)$ , where $c$ is positive parameter, is of

The correct option is C order $= 1$ , degree $= 3$
$y^{2} = \sqrt{c} (x + 2 c)$
Differentiating w.r.t. $x$ ,
$2 y \frac{d y}{d x} = \sqrt{c}$
$∴ y^{2} = 2 y \frac{d y}{d x} (x + 2 {(2 y \frac{d y}{d x})}^{2})$

Hence order $= 1$ , degree $= 3$