The differential equation representing the family of ellipses having foci either on the x-axis or on the y-axis, centre at the origin and passing through the point (0, 3) is :
A
xyy′–y2+9=0
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B
xyy′′–x(y′)2−yy′=0
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C
xyy′–y2−9=0
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D
x+yy′′=0
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Solution
The correct option is Axyy′–y2+9=0 According to the question general equation of ellipse is x2a2+y2b2=1As the ellipse passes through(0,3) x2a2+y29=1........(1) Now differentiate w.r.t x xa2=−y9dydx⇒1a2=−y9xy′........(2) From (1) and (2) Differential equation is xyy′−y2+9=0