wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The differential equation whose general solution is y=Acos(x+3), where A is arbitrary constant is

A
cot(x+3)y1+y=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
tan(x+3)y1+y=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
cot(x+3)y1y=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
tan(x+3)y1y=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A cot(x+3)y1+y=0
Given,
y=Acos(x+3)......(1).

Differentiating both sides w.r.t x we get,

dydx=Asin(x+3)

dydx=y×sin(x+3)cos(x+3) [ Using (1) ]

y1cot(x+3)+y=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Formation of Differential Equation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon