Question

The diffraction of barium with X-radiation of wavelength 2.29 $A^o$ gives a first order reflection at ${30}^o$. What is the distance between the diffracted planes?

• A. 1.15 $A^o$
• B. 2.29 $A^o$
• C. 2.40 $A^o$
• D. 2.60 $A^o$

Answer 1

The correct option is B 2.29 $A^o$

$n=1,lambda=2.29$ $A^o$
$sin\theta =sin{30}^o$
$d=?$
$2dsin\theta =n\lambda$
$2\times d\times sin{30}^o=1\times 2.29$
$d=\frac{1\times 2.29}{2\times sin{30}^o}=2.29$ $A^o$