The diffusion of $O_{2}$ into blood at the surface of alveoli results in all the following consequences except:

Reverse chloride shift

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H C O_{3}^{-}

leaves the

R B C_{s}

in the exchange of

C I^{-}

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Dissociation of

C O_{2}

from haemoglobin

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Dissociation of

H^{+}

from

H H b

(haemoglobinic acid)

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Solution

The correct option is B $H C O_{3}^{-}$ leaves the $R B C_{s}$ in the exchange of $C I^{-}$
When the oxygen diffuses from alveoli into the blood, carbon dioxide is emitted outside into the alveoli. For that, the bicarbonate ions move into the RBCs where they combine with protons to liberate carbon dioxide. The carbon dioxide comes out into the alveoli. The chloride ions move out in response to bicarbonate ions entry into the red blood cells. This is called a Reverse Chloride shift.
So, the correct option is 'HCO $_{3}$ - leaves the RBCs in the exchange of Cl $-$ '

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Similar questions

In the transport of CO2 from the tissues to the lungs which of the following occurs in the venous blood?

A) conversion of CO2 and H2O to H+ and HCO3-- in the RBC'S

B) Buffering of H+ by oxy haemoglobin

C) Shifting of HCO3-- into the RBC'S from plasma in exchange for Cl-

D)Alkalinization of RBC's

O_{2}

O_{2}

In lungs, there is an exchange of ions between RBC and Plasma. Removal of $C O_{2}$ from blood involves ______________.

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