Question

The digit at the tens place of a two digit number is three times the digit at the units place, If digits are reversed, the new number will be $36$ less than the original number. Find the number.

Answer 1

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,$x=3y\cdots \left(i\right)$

Reversed number = 10y + x

A.t.Q :- $(10x+y)-(10y+x)=36$ Put x = 3y in eq. (i)

$\Rightarrow 9x-9y=36$

$\Rightarrow x-y=4\cdots \left(ii\right)$

$\Rightarrow 3y-y=4$

$\therefore 2y=4$ $x=3y$ $\therefore x=6$

$y=2$

$\therefore$ Number = 62