The digit in the ten's place of a two-digit number is three times that in the one's place. if the digit are reversed the new number will be 36 less than the original number. Find the number.

64

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52

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62

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42

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Solution

The correct option is C $62$
Let the digit in ten's place = $t$
digit at one's place be = $s$
Now, $t = 3 s$
Also, $10 t + s - (10 s + t) = 36$
$9 t - 9 s = 36$
$t - s = 4$
or, $3 s - s = 4$
$s = 2$
and, $t = 3 \times 2 = 6$
Thus, the number is $62$

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The digit in the ten's place of a two-digit number is three times that in the one's place. if the digit are reversed the new number will be 36 less than the original number. Find the number.

The correct option is C 62Let the digit in ten's place =tdigit at one's place be = sNow,t=3sAlso, 10t+s−(10s+t)=369t−9s=36t−s=4or, 3s−s=4s=2and, t=3×2=6Thus, the number is 62

The correct option is C $62$
Let the digit in ten's place = $t$
digit at one's place be = $s$
Now, $t = 3 s$
Also, $10 t + s - (10 s + t) = 36$
$9 t - 9 s = 36$
$t - s = 4$
or, $3 s - s = 4$
$s = 2$
and, $t = 3 \times 2 = 6$
Thus, the number is $62$