The digit whose place value remains fixed is one. how? can you explain this.
A number is formed by grouping the digits together.
● Each digit has a fixed position called its place.
● Each digit has a value depending on its place called the place value of the digit.
● The face value of a digit for any place in the given number is the value of the digit itself
● Place value of a digit = (face value of the digit) × (value of the place)
1. The place value of every one-digit number is the same as and equal to its face value.
(i) Place value and face value of 1, 2, 3, 4, 5, 6, 7, 8 and 9 are 1, 2, 3, 4, 5, 6, 7, 8 and 9 respectively.
(ii) The place value of zero (0) is always 0. It may hold any place in a number, its value is always 0.
As, in 105, 350, 42017, 90218 the place value of 0 in each number is 0.
2. In a two-digit number, the place value of the ten-place digit is 10 times of the digit.
As, in 58, the place value of 5 is 5 × 10 = 50 and place value of 8 is 8 × 1= 8; the face value of 5 is 5 and of 8 is 8.
3. In the number 475, the digit 5 is at one’s place, digit 7 is at ten’s place and digit 4 is at hundred’s place.
So, place value of 5 = 5, place value of 7 = 7 × 10 = 70, and place value of 4 is 4 × 100 = 400.
Thus, for the place value of a digit, the digit is multiplied by the place value of 1 it has to be that place.