CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Quantitative Aptitude

Lower Limit

The digits ...

Question

The digits $1, 2, 3, 4, 5, 6, 7, 8$ and $9$ are written in random order to form a nine-digit number. The probability that the number is divisible by $4$ , is?

Open in App

Solution

For number to be divisible by 4 last two digits must be divisible by 4
So favourable choices of last 4 digits are
12,16,24,28,32,36,48,52,56,64,68,72,76,84,92,96=16
Total formed favourable number=167!
Total numbers formed=9!
Probability=167!/9!=2/9

Suggest Corrections

thumbs-up

0

Similar questions

1, 2, 3, 4, 5, 6, 7, 8

9

are written in random order to form a nine digit number. Let

p

be the probability that this number is divisible by

36

9 p

Q. Seven digits from the numbers

1, 2, 3, 4, 5, 6, 7, 8

9

are written in random order. The probability that this seven-digit number is divisible by

9

\frac{k}{9}

k

?

Q. Seven digits from the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 are written down non-repeatedly in a random order to form a seven digit number. The probability that this seven digit number is divisible by 9 is

1, 2, 4

6

are selected at random to form a four digits numbers. What is the probability that the number so formed, would be divisible by

4

?

Q. A five-digit number is written down at random. The probability that the number is divisible by

5

and no two consecutive digits are identical, is

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

QUANTITATIVE APTITUDE

Watch in App

explore_more_icon

Explore more

Other Quantitative Aptitude

Join BYJU'S Learning Program

CrossIcon