The digits of a two digit number differ by 2. If the digits are interchanged and resulting number is added to the original number we get 88.
What is the original number?
53
Given : The difference between the digits is 2.
So, if unit's place digit is x then ten’s place will be x + 2,then the number will be 10(x + 2) + x.
After reversing the digit the number will be 10x + x + 2.
10(x + 2) + x + 10x + x + 2 = 88 (given)
10x + 20 + x + 10x + x + 2 = 88
22x + 22 = 88
22x = 88 - 22 = 66
x = 66 ÷ 22 = 3
∴The number is 53.