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Question
The digits of a two digit number differ by 2. If the digits are interchanged and resulting number is added to the original number we get 88.
What is the original number?
The digits of a two digit number differ by 2. If the digits are interchanged and resulting number is added to the original number we get 88.
What is the original number?
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Solution
The correct option is D 53
Given : The difference between the digits is 2.
So, if unit's place digit is x then ten’s place will be x + 2,then the number will be 10(x + 2) + x.
After reversing the digit the number will be 10x + x + 2.
10(x + 2) + x + 10x + x + 2 = 88 (given)
10x + 20 + x + 10x + x + 2 = 88
22x + 22 = 88
22x = 88 - 22 = 66
x = 66 ÷ 22 = 3
∴The number is 53.
53
Given : The difference between the digits is 2.
So, if unit's place digit is x then ten’s place will be x + 2,then the number will be 10(x + 2) + x.
After reversing the digit the number will be 10x + x + 2.
10(x + 2) + x + 10x + x + 2 = 88 (given)
10x + 20 + x + 10x + x + 2 = 88
22x + 22 = 88
22x = 88 - 22 = 66
x = 66 ÷ 22 = 3
∴The number is 53.
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