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Question

The digits of the number 122311 are arranged in all possible ways. The number of all different number greater than 3,00,000 are

A
12
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B
32
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C
10
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D
120
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Solution

The correct option is C 10
Given, Number is 122311
The number of all different number should be greater than 3,00,000
1st digit will be fixed that is 3 and rest 5 digits can be arranged in 5! ways and 1 is repeated trice so divide by 3! and 2 is repeated twice so divide be 2!
the no of ways are 5!2!3!=10
Hence option C is correct

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